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algorithm/Codility7

Codility[Lesson 6] - Sorting(MaxProdictOfThree) A non-empty array A consisting of N integers is given. The product of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N). For example, array A such that: A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6 contains the following example triplets: (0, 1, 2), product is −3 * 1 * 2 = −6(1, 2, 4), product is 1 * 2 * 5 = 10(2, 4, 5), product is 2 * 5 * 6 = 60 Your goal is to find.. 2021. 8. 27.
Codility[Lesson 3] - Time Complexity(TapeEquilibrium) A non-empty array A consisting of N integers is given. Array A represents numbers on a tape. Any integer P, such that 0 < P < N, splits this tape into two non-empty parts: A[0], A[1], ..., A[P − 1] and A[P], A[P + 1], ..., A[N − 1]. The difference between the two parts is the value of: |(A[0] + A[1] + ... + A[P − 1]) − (A[P] + A[P + 1] + ... + A[N − 1])| In other words, it is the absolute differ.. 2021. 8. 26.
Codility[Lesson 3] - Time Complexity(PermMissingElem) An array A consisting of N different integers is given. The array contains integers in the range [1..(N + 1)], which means that exactly one element is missing. Your goal is to find that missing element. Write a function: class Solution { public int solution(int[] A); } that, given an array A, returns the value of the missing element. For example, given array A such that: A[0] = 2 A[1] = 3 A[2] =.. 2021. 8. 26.
Codility[Lesson 3] - Time Complexity(FrogJmp) A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D. Count the minimal number of jumps that the small frog must perform to reach its target. Write a function: class Solution { public int solution(int X, int Y, int D); } that, given three inte.. 2021. 8. 26.